Plotly: How To Select Graph Source Using Dropdown?

I'm trying to embed multiple, selectable graphs in a single figure using Plotly, using a dropdown figure. I followed the dropdown example from Plotly, but they only show how to cha

Solution 1:

Updated answer using graph_objects:

As of version 4, you don't have to worry about offline versus online functionality. So drop the from plotly import graph_objs as go, offline as po and po.init_notebook_mode(), and just use import plotly.graph_objects as go. I've updated my original answer with a complete code snippet that shows the whole approach with multiple traces using plotly.graph_objects at the end. The solution to the question as it still stands will still be the same, namely:

---

'y' in updatemenus does not take a single list as an argument, but rather a list of lists like in 'y' = [values_1] where values_1 is a list in itself. So just replace your lines

• {'y': json.dumps(values_1)}, and {'y': json.dumps(values_2)},

with

• {'y': [values_1]}, and {'y': [values_2]},

to get these plots for the different options Val 1 and Val 2:

---

---

Some Details:

Values_1 is, unsurprisingly, a list of length 100 where each element is of type numpy.float. Replacing json.dumps(values_1) with values_1, and json.dumps(values_2) with values_2 will render the same plots as in your question. The reason why these plots are just straight lines, seems to be that it's the length of your lists that are being plotted, and not the values contained in that list. Or something to that effect.

Setting 'y' = values_1 is the same thing as assigning a single list to 'y'. But 'y' in updatemenus does not take a single list as an argument, but rather a list of lists like in 'y' = [values_1]. Why? Because you might want to plot multiple lists in the same figure like 'y' = [values_1, values_1b]. Have a look:

Plot for dropdown option Var 1:

Plot for dropdown option Var 2

Complete original code:

import plotly
from plotly import graph_objs as go, offline as po, tools
po.init_notebook_mode()

import numpy as np
import json

x = list(np.linspace(-np.pi, np.pi, 100))
values_1 = list(np.sin(x))
values_1b = [elem*-1 for elem in values_1]

values_2 = list(np.tan(x))
values_2b = [elem*-1 for elem in values_2]


line = go.Scatter(
    x=x,
    y=values_1
)

line2 = go.Scatter(
    x=x,
    y=values_1b
)


updatemenus = [
    {
        'buttons': [
            {
                'method': 'restyle',
                'label': 'Val 1',
                'args': [
                    {'y': [values_1, values_1b]},
                ]
            },
            {
                'method': 'restyle',
                'label': 'Val 2',
                'args': [
                    {'y': [values_2, values_2b]},
                ]
            }
        ],
        'direction': 'down',
        'showactive': True,
    }
]

layout = go.Layout(
    updatemenus=updatemenus,
)

figure = go.Figure(data=[line, line2], layout=layout)
po.iplot(figure)

Complete updated code:

# imports
import plotly.graph_objects as go
import numpy as np

# data
x = list(np.linspace(-np.pi, np.pi, 100))
values_1 = list(np.sin(x))
values_1b = [elem*-1 for elem in values_1]
values_2 = list(np.tan(x))
values_2b = [elem*-1 for elem in values_2]

# plotly setup]
fig = go.Figure()

# Add one ore more traces
fig.add_traces(go.Scatter(x=x, y=values_1))
fig.add_traces(go.Scatter(x=x, y=values_1b))

# construct menus
updatemenus = [{'buttons': [{'method': 'update',
                             'label': 'Val 1',
                             'args': [{'y': [values_1, values_1b]},]
                              },
                            {'method': 'update',
                             'label': 'Val 2',
                             'args': [{'y': [values_2, values_2b]},]}],
                'direction': 'down',
                'showactive': True,}]

# update layout with buttons, and show the figure
fig.update_layout(updatemenus=updatemenus)
fig.show()

Plot with version 4 default layout: