Python - Sort A List Of Dics By Value Of Dict`s Dict Value

I have a list that looks like this: persons = [{'id': 11, 'passport': {'id': 11, 'birth_info':{'date': 10/10/2016...}}},{'id': 22, 'passport': {'id': 22, 'birth_info':{'date': 11/1

Solution 1:

The function sorted() provides the key argument. One can define a callable which returns the key to compare the items:

sorted(persons, key=lambda x: x['passport']['birth_info']['date'])

The argument x is an item of the given list of persons.

If the dates are strings you could use the datetime module:

sorted(persons, key=lambda x: datetime.datetime.strptime(x['passport']['birth_info']['date'], '%m/%d/%Y'))

Solution 2:

Try this

from datetime import datetime


print(sorted(persons, key=lambda x: datetime.strptime(x['passport']['birth_info']['date'], "%d/%m/%Y"))) #reverse=True for descending order.