Getting The Function For A Compiled Function Object
Solution 1:
Through the inspect.getframeinfo
module.
I mean -- there is no straightforward way of doing that in Python -- Most times you can get hold of the code object, without having the function already, it is through frame instrospection.
Inspect's getframeinfo function does return some information about the frame being run, then you can retrieve the function object by getting its name.
Tough this is implementation dependent and have some drawbacks:
>>> import inspect
>>> def a():
... return inspect.currentframe()
...
>>> inspect.getframeinfo(a())
Traceback(filename='<stdin>', lineno=2, function='a', code_context=None, index=None)
>>> b = inspect.getframeinfo(a())
>>> b.function
'a'
Another way, but still implementation dependent, is to use the gc module (garbage collector) to get referrers to said code object.
>>> import gc
>>> from types import FunctionType
>>> def a(): pass
...
>>> code = a.__code__
>>> [obj for obj in gc.get_referrers(code) if isinstance(obj, FunctionType) ][0]
<function a at 0x7f1ef4484500>
>>>
--
This is for Python 3 - for Python 2 one should replace __code__
by func_code
Solution 2:
You can retrieve the function-object as an attribute of the module or the class:
import inspect
import sys
def frame_to_func(frame):
func_name = frame.f_code.co_name
if "self" in frame.f_locals:
return getattr(frame.f_locals["self"].__class__, func_name)
else:
return getattr(inspect.getmodule(frame), func_name)
def tracefunc(frame, event, arg):
if event in ['call', 'return']:
func_obj = frame_to_func(frame)
print(f"{event} {frame.f_code.co_name} {func_obj.__annotations__}")
def add(x: int, y: int) -> int:
return x+y
if __name__ == '__main__':
sys.settrace(tracefunc)
add(1, 2)
sys.settrace(None)
Output:
call add {'x': <class 'int'>, 'y': <class 'int'>, 'return': <class 'int'>}
The solution is inspired by this question.
Post a Comment for "Getting The Function For A Compiled Function Object"