How To Break A Dictionary Into A List Of Dictionaries In Python?

I'm trying to convert a dictionary into a list, which contains many dictionaries. for example: input: { 'first-name':'foo', 'last-name':'bar', 'gender':'unknown', '

Solution 1:

Using list comprehension

• items() method is used to return the list with all dictionary keys with values.

Ex.

dict1 = {
    'first-name':'foo',
    'last-name':'bar',
    'gender':'unknown',
    'age':99
}

new_list = [{k:v} for k,v in dict1.items() ]
print(new_list)

O/P:

[{'first-name': 'foo'}, {'last-name': 'bar'}, {'gender': 'unknown'}, {'age': 99}]

Another solution suggested by @josoler

new_list = list(map(dict, zip(dict1.items())))

Solution 2:

Dict = {
    'first-name':'foo',
    'last-name':'bar',
    'gender':'unknown',
    'age':99
}
list = [(key, value) for key, value inDict.items()]

list >> [('first-name':'foo'), ('last-name':'bar'), ('gender':'unknown'),('age':99)]

This is the simplest way to Convert dictionary to list of tuples

Reference : Python | Convert dictionary to list of tuples

Solution 3:

>>> d={
... 'first-name':'foo',
... 'last-name':'bar',
... 'gender':'unknown',
... 'age':99... }
>>> [{k: v} for (k, v) in d.items()]
[{'first-name': 'foo'}, {'last-name': 'bar'}, {'gender': 'unknown'}, {'age': 99}]

Solution 4:

An alternative method:

>>> [dict([i]) for i in d.items()]
[{'gender': 'unknown'}, {'age': 99}, {'first-name': 'foo'}, {'last-name': 'bar'}]

Solution 5:

k={
    'first-name':'foo',
    'last-name':'bar',
    'gender':'unknown',
    'age':99
}

s =list(map(lambda x:{x[0]:x[1]},k.items() ))

output

[{'first-name': 'foo'},
 {'last-name': 'bar'},
 {'gender': 'unknown'},
 {'age': 99}]