How To Tell An Infinite Loop To End Once One Number Repeats Twice In A Row (in Python 3.4)

The title says it all. I have an infinite loop of randomly generated numbers from one to six that I need to end when 6 occurs twice in a row.

Solution 1:

The following is a working example. With comments in the code so you can better understand each step.

# import required to use randintimport random

# holds the last number to be randomly generated
previous_number = NonewhileTrue: # infinite loop# generates a random number between 1 and 6
    num = random.randint(1, 6)
    # check if the last number was 6 and current number is 6if previous_number == 6and num == 6:
        # if the above is true then break out the loopbreak# store the latest number and start the loop again
    previous_number = num 

Solution 2:

just break when the appropriate condition is met. break leaves the loop instantly.

while True:
   # ...
   if last_val == val == 6:
      break
   last_val=val # save valfor next iteration

Solution 3:

    y = 0while1:
        # --> "random Generator" rNumber
        if rNumber == 6:
            y +=1else: 
            y = 0if y == 2:
            break