Does Raising A Manual Exception In A Python Program Terminate It?

Does invoking a raise statement in python cause the program to exit with traceback or continue the program from next statement? I want to raise an exception but continue with the r

Solution 1:

I want to raise an exception but continue with the remainder program.

There's not much sense in that: the program control either continues through the code, or ripples up the call stack to the nearest try block.

Instead you can try some of:

• the traceback module (for reading or examining the traceback info you see together with exceptions; you can easily get it as text)
• the logging module (for saving diagnostics during program runtime)

Example:

def somewhere():
    print'Oh no! Where am I?'
    import tracebackprint''.join(traceback.format_stack())  # ortraceback.print_stack(sys.stdout)
    print'Oh, here I am.'

def someplace():
    somewhere()

someplace()

Output:

Oh no! Where am I?
  File "/home/kos/exc.py", line 10, in <module>
    someplace()
  File "/home/kos/exc.py", line 8, in someplace
    somewhere()
  File "/home/kos/exc.py", line 4, in somewhere
    print''.join(traceback.format_stack())

Oh, here I am.

Solution 2:

Only an uncaught exception will terminate a program. If you raise an exception that your 3rd-party software is not prepared to catch and handle, the program will terminate. Raising an exception is like a soft abort: you don't know how to handle the error, but you give anyone using your code the opportunity to do so rather than just calling sys.exit().

If you are not prepared for the program to exit, don't raise an exception. Just log the error instead.