Django - How To Get The Contents Of A {% Block %} Tag From A Template
I got this far: >>> some_template = get_template_from_string( ... load_template_source( ... 'some_template.html', ... settings.TEMPLATE_DIRS)) ... >
Solution 1:
This seems like you're working hard against the Django grain. Put the content into an include file, then {% include %}
it in your block, and also read the file directly. If you could tell us more about what you're trying to accomplish, there's probably a better way to do it.
Solution 2:
The solution I created:
import re
BLOCK_RE = re.compile(r'{%\s*block\s*(\w+)\s*%}')
NAMED_BLOCK_RE = r'{%%\s*block\s*%s\s*%%}'# Accepts string formatting
ENDBLOCK_RE = re.compile(r'{%\s*endblock\s*(?:\w+\s*)?%}')
defget_block_source(template_source, block_name):
"""
Given a template's source code, and the name of a defined block tag,
returns the source inside the block tag.
"""# Find the open block for the given name
match = re.search(NAMED_BLOCK_RE % (block_name,), template_source)
if match isNone:
raise ValueError(u'Template block {n} not found'.format(n=block_name))
end = inner_start = start = match.end()
end_width = 0whileTrue:
# Set ``end`` current end to just out side the previous end block
end += end_width
# Find the next end block
match = re.search(ENDBLOCK_RE, template_source[end:])
# Set ``end`` to just inside the next end block
end += match.start()
# Get the width of the end block, in case of another iteration
end_width = match.end() - match.start()
# Search for any open blocks between any previously found open blocks,# and the current ``end``
nested = re.search(BLOCK_RE, template_source[inner_start:end])
if nested isNone:
# Nothing found, so we have the correct end blockbreakelse:
# Nested open block found, so set our nested search cursor to just# past the inner open block that was found, and continue iteration
inner_start += nested.end()
# Return the value between our ``start`` and final ``end`` locationsreturn template_source[start:end]
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