List Minimum In Python With None?

Is there any clever in-built function or something that will return 1 for the min() example below? (I bet there is a solid reason for it not to return anything, but in my particula

Solution 1:

None is being returned

>>> printmin([None, 1,2])
None>>> None < 1True

If you want to return 1 you have to filter the None away:

>>>L = [None, 1, 2]>>>min(x for x in L if x isnotNone)
1

Solution 2:

using a generator expression:

>>>min(value for value in [None,1,2] if value isnotNone)
1

eventually, you may use filter:

>>>min(filter(lambda x: x isnotNone, [None,1,2]))
1

Solution 3:

Make None infinite for min():

defnoneIsInfinite(value):
    if value isNone:
        returnfloat("inf")
    else:
        return value

>>> printmin([1,2,None], key=noneIsInfinite)
1

Note: this approach works for python 3 as well.