"can Only Iterable" Python Error

Hello my fellow programmers. I am a fairly new programmer, and now I am facing a great predicament. I am getting the error: can only assign an iterable Firstly I don't know what t

Solution 1:

int_lis[:] = duplic_int_lis [int_firs] means assign all the items of duplic_int_lis [int_firs] to int_lis, so it expects you to pass an iterable/iterator on the RHS.

But in your case you're passing it an non-iterable, which is incorrect:

>>> lis = range(10)
>>> lis[:] = range(5) 
>>> lis               #all items of `lis` replaced with range(5)
[0, 1, 2, 3, 4]

>>> lis[:] = 5#Non-iterable will raise an error.
Traceback (most recent call last):
  File "<ipython-input-77-0704f8a4410d>", line 1, in <module>
    lis[:] = 5
TypeError: can only assign an iterable

>>> lis[:] = 'foobar'#works for any iterable/iterator>>> lis
['f', 'o', 'o', 'b', 'a', 'r']

As you cannot iterate over an integer, hence the error.

>>> for x in1: pass
Traceback (most recent call last):
  File "<ipython-input-84-416802313c58>", line 1, in <module>
    for x in1:pass
TypeError: 'int'objectisnot iterable

Solution 2:

The RHS of a slice-assignment must be an iterable, not a scalar. Consider slice-deleting and then appending instead.

Solution 3:

An iterable is a thing with multiple items that you can iterate through (for example: take the 1st value do something, then the 2nd do something, etc...) Lists, dictionaries, tuples, strings have several items in them and can be used as iterables. As a counterexample: number types don't qualify as iterable.

Remember that computers count from #0 so: if you want the first value of a list you can use

my_list[0]

before you go further I would suggest watching this video about looping. https://www.youtube.com/watch?v=EnSu9hHGq5o