Filter List Of Values In A Dictionary

I have a dictionary called hash_vs_file keys are file_hash values are file_path (a list of one or more filepaths) I want to isolate and print only the items where the list is longe

Solution 1:

Use iteritems() this way instead:

for file_hash, file_path in hash_vs_file.iteritems():
    iflen(file_path) > 1:   
        print file_path
        print file_hash

Because the way you did, you are getting only the keys of the dictionary so checking the length of file_path fails.

Update:

You asked for the readability of the output. You can inspire yourself from this method:

print file_path, file_hash

Or this better one which relies on format():

print"File Path: {} ------ File Hash: {}".format(file_path,file_hash)

Or, if you want it to look like a list, try this instead:

print"[{}, {}]".format(file_path,file_hash)

Solution 2:

for file_hash, file_path in hash_vs_file.items():
    iflen(file_path) > 1:   
        print file_hash
        print file_path

The method .items() gives you a tuple of key and value. You can unpack this tuple with file_hash, file_path, so that you have access to each file_hash and file_path in each iteration.

Solution 3:

Alternatively, you can use the filter built in function to return an iterator like so:

for file_hash infilter(lambda key: len(hash_vs_file[key]) > 1, hash_vs_file):
    print("{} : {}".format(file_hash, hash_vs_file[file_hash]))

Or you can use dict comprehension for a newly filtered dictionary:

hash_vs_file = {fhash: fpath for fhash, fpath in hash_vs_file.items() iflen(fpath) > 1}
print(hash_vs_file)