Python: Timeout Exception Handling With Signal.alarm
Solution 1:
if a function call is taking too long
I realize that this might not be obvious for inexperienced developers, but the methods applicable for approaching this problem entirely depend on what you are doing in this "busy function", such as:
Is this a heavy computation? If yes, which Python interpreter are you using? CPython or PyPy? If CPython: does this computation only use Python bytecode or does it involve function calls outsourced to compiled machine code (which may hold Python's Global Interpreter Lock for quite an uncontrollable amount of time)?
Is this a lot of I/O work? If yes, can you abort this I/O work in an arbitrary state? Or do you need to properly clean up? Are you using a certain framework such as gevent or Twisted?
Edit: So, it looks you are just spawning a subprocess and wait for it to terminate. Great, that is actually one of the most simple problems to implement a timeout control for. Python (3) ships a corresponding feature! :-) Have a look at
https://docs.python.org/3/library/subprocess.html#subprocess.call
The timeout argument is passed to Popen.wait(). If the timeout expires, the child process will be killed and then waited for again. The TimeoutExpired exception will be re-raised after the child process has terminated.
Edit2:
Example code for you, save this to a file and execute it with Python 3.3, at least:
import subprocess
try:
subprocess.call(['python', '-c', 'print("hello")'], timeout=2)
except subprocess.TimeoutExpired as e:
print("%s was terminated as of timeout. Its output was:\n%s" % (e.cmd, e.output))
try:
subprocess.call(['python'], timeout=2)
except subprocess.TimeoutExpired as e:
print("%s was terminated as of timeout. Its output was:\n%s" % (e.cmd, e.output))
In the first case, the subprocess immediately returns. No timeout exception will be raised. In the second case, the timeout expires, and your controlling process (the process running above's script) will attempt to terminate the subprocess. This succeeds. After that, the subprocess.TimeoutExpired
is raised and the exception handler deals with it. For me the output of the script above is ['python'] was terminated as of timeout. Its output was:
None
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