Return All The Keys (as Set) From Num_dict That Have Value Greater Than Or Equal To Min_cutoff

Parameters num_dict: dictionary all values are numeric min_cutoff: float Compare with the num_dict values. Return all keys where their values >= min_cutoff. My dictionary is

Solution 1:

defkeys_get_cutoff(dict, min_value):

    return [key for key indict.keys() ifdict[key] >= min_value]

Solution 2:

Using list comprehension. see more details about list comprehension

Ex.

num_dict =  {'Denver': 200, 'Houston': 100, 'NOLA':50}
min_cutoff = 51
num_dict_keys = [k for k, v in num_dict.items() if v >= min_cutoff ]
print(num_dict_keys)

O/P:

['Denver', 'Houston']