Rounding A Percentage In Python

if act == 'block' and enemy_decision != 2: percentage_blocked = (enemy_attack - block)/(enemy_attack) * 100 print('You have blocked %s percent of the enemy's attack.' % per

Solution 1:

I think the standard round function should work

round(percentage_blocked,1)

Solution 2:

You can use the template string like this and {0:.1f} means, the first parameter has to be formatted to be with 1 decimal digit

print("You have blocked {0:.1f} percent of the enemy's attack.".format(percentage_blocked))

Solution 3:

You could use {:.1%} format:

blocked = (enemy_attack - block) / enemy_attack
print("You have blocked {:.1%} percent of the enemy's attack.".format(blocked))

Notice: there is no * 100.

Solution 4:

print("You have blocked %.1f percent of the enemy's attack." % percentage_blocked)

Solution 5:

Alternate solution.

percentage_blocked = int(
           ((enemy_attack - block)/(enemy_attack) * 100)*10 + 0.5)/10

Round it while calculating. int(x+0.5) rounds x properly