Parse Mailto Urls In Python

I'm trying to parse mailto URLs into a nice object or dictionary which includes subject, body, etc. I can't seem to find a library or class that achieves this- Do you know of any?

Solution 1:

You can use urlparse and parse_qs to parse urls with mailto as scheme. Be aware though that according to scheme definition:

mailto:me@mail.com,you@mail.com?subject=mysubject

is identical to

mailto:?to=me@mail.com&to=you@mail.com&subject=mysubject

Here's an example:

from urlparse import urlparse, parse_qs
from email.message import Message

url = 'mailto:me@mail.com?subject=mysubject&body=mybody&to=you@mail.com'
msg = Message()
parsed_url = urlparse(url)

header = parse_qs(parsed_url.query)
header['to'] = header.get('to', []) + parsed_url.path.split(',')

for k,v in header.iteritems():
    msg[k] = ', '.join(v)

print msg.as_string()

# Will print:# body: mybody# to: me@mail.com, you@mail.com# subject: mysubject

Solution 2:

The core urlparse lib does less than a stellar job on mailtos, but gets you halfway there:

In [3]: from urlparse import urlparse

In [4]: urlparse("mailto:me@mail.com?subject=mysubject&body=mybody")
Out[4]: ParseResult(scheme='mailto', netloc='', path='me@mail.com?subject=mysubject&body=mybody', params='', query='', fragment='')

EDIT

A little research unearths this thread. Bottom line: python url parsing sucks.

Solution 3:

Seems like you might just want to write your own function to do this.

Edit: Here is a sample function (written by a python noob).

Edit 2, cleanup do to feedback:

from urllib import unquote
test_mailto = 'mailto:me@mail.com?subject=mysubject&body=mybody'

def parse_mailto(mailto):
   result = dict()
   colon_split = mailto.split(':',1)
   quest_split = colon_split[1].split('?',1)
   result['email'] = quest_split[0]

   for pair in quest_split[1].split('&'):
      name = unquote(pair.split('=')[0])
      value = unquote(pair.split('=')[1])
      result[name] = value

   return result

print parse_mailto(test_mailto)

Solution 4:

Here is a solution using the re module...

import re

d={}
def parse_mailto(a):
  m=re.search('mailto:.+?@.+\\..+?', a)
  email=m.group()[7:-1]
  m=re.search('@.+?\\..+?\\?subject=.+?&', a)
  subject=m.group()[19:-1]
  m=re.search('&.+?=.+', a)
  body=m.group()[6:]

  d['email']=email
  d['subject']=subject
  d['body']=body

This assumes it is in the same format as you posted. You may need to make modifications to better fit your needs.

Solution 5:

Batteries included: urlparse.