Python Socket Object Accept Time Out

Question: Is there some sort of time out or interrupt to the socket.accept() function in python? Info: I have a program that has a child thread bound to a port and constantly acce

Solution 1:

You can use settimeout() as in this example:

import socket

tcpServer = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 
tcpServer.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
tcpServer.settimeout(0.2) # timeout for listening
tcpServer.bind(('0.0.0.0', 10000)) # IP and PORT
tcpServer.listen(1)

stopped = Falsewhilenot stopped:
  try: 
    (conn, (ip, port)) = tcpServer.accept() 
  except socket.timeout:
    passexcept:
    raiseelse:
    # work with the connection, create a thread etc.
    ...

The loop will run until stopped is set to true and then exit after (at most) the timeout you have set. (In my application I pass the connection handle to a newly created thread and continue the loop in order to be able to accept further simultaneous connections.)

Solution 2:

You can set the default timeout with

import socket
print socket.getdefaulttimeout()
socket.setdefaulttimeout(60)

AFAIK This will affect all the socket operation

Solution 3:

Maybe settimeout() is what you're looking for.