Best Method In Writing A List To A Text File In Python?

import pandas import sys import os import csv import string f=open(myfile,'r') lines=f.readlines() x=[] for i in lines: x.append(i.split()[3]); f.close() if not os.path.e

Solution 1:

Since you are importing pandas, why don't you use it, too.

data = pd.read_table(myfile, header=None, sep='\s+')
data.columns ='t','x','y','z','Rx','Ry','Rz'forcolumnin data:
    withopen(column+ ".txt", "w") as ofile:
        ofile.write(' '.join(str(i) for i in data[column]))

Solution 2:

So if i understand the filestructure you want correctly:

you want each line to have 7 numbers in order "t z y x Rz Ry Rx" with space between them.

First you need to go through first element of all lists, than through second, etc...

To do so best may be zip (documentation)

withopen(filename, 'w') as f:  # We open file for writingfor line inzip(t, z, y, x, Rz, Ry, Rx):
        line = [str(i) for i in line]  # convert to strings
        f.write(' '.join(line) + "\n")  # joins space and ends the line

EDIT:

Ok, so if I now understand the format, the following shoud help:

withopen('x.txt', 'w') as f:
    f.write('\n'.join([str(i) for i in x]) + '\n')  # omit "+ '\n'" if you don't want newline at the end of the file.

Repeate for each variable.

EDIT 2:

My explanation for why your methods don't work:

method 1

It's just how csv writer's writerows work

method 2

you are doing for each item in x, where x is list, not file you can write to. Corrected code:

withopen('x.txt', 'w') as f:
    for item in x:
        f.write(str(item) + '\n')

note that '%s\n' can't work as item is int and s is for string, f.write('%d\n' % item) shoud work

method 3

str(x) formats list to the form you see it in file and you just write that into the file. The formating can be seen by doing print(str(x))

method 4

again same as in method 2

method 5

Similar to method 2. You don't define number anywhere. For it to work use:

withopen('x.txt', 'w') asf:
    fornumberinx:
        f.write('%d\n' % number)