Assign The Result Of A Loop To A Variable In Python

Consider a list I want to parse using a for : friends = ['Joe', 'Zoe', 'Brad', 'Angelina', 'Zuki', 'Thandi', 'Paris'] for i in friends: print i will return : 'Joe', 'Zoe', 'Bra

Solution 1:

If I understand well, you'd like to dynamically create variables. Here it is.

from collections import OrderedDict

friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
d = OrderedDict()
for idx, value inenumerate(friends):
    key = 'var' + str(idx)
    d[key] = value 

print(d)
# Output
OrderedDict([('var0', 'Joe'), ('var1', 'Zoe'), ('var2', 'Brad'), ('var3', 'Angelina'), ('var4', 'Zuki'), ('var5', 'Thandi'), ('var6', 'Paris')])

Solution 2:

I also have this question, this is how I managed to solve it somewhat:

    friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]

    new_friends = ' '.join([x for x in friends])

    print(new_friends)

Will return:

    Joe Zoe Brad Angelina Zuki Thandi Paris

Solution 3:

var = ''
friends = ["Joe", "Zoe", "Brad", "Angelina", "Zuki", "Thandi", "Paris"]
for i in friends:
    var=i 

if list and loop are in function then declare var as global

globalvar

in starting of function

Solution 4:

If you want to join the values in friends into a comma-separated string, that would be

s = ','.join(friends)

If you want to include quotes around the names, maybe something like

s = ','.join(['"{0}"'.format(x) for x in friends])

Solution 5:

Try this at the end of the loop:

the_variable = the_variable + i

However, if you are to do this, you should add a space to the end of every item in the dictionary, otherwise it will output:

JoeZoeBradAngelinaZukiThandiParis