How Can I Merge Two Argparse Namespaces In Python 2.x?
I want to merge 2 argparse.Namespace objects in Python 2.x. In python 3.x I can do something like this: from argparse import Namespace # The 2 initial objects options_foo = Namesp
Solution 1:
Here is a function that merges two args:
defmerge_args_safe(args1: Namespace, args2: Namespace) -> Namespace:"""
Merges two namespaces but throws an error if there are keys that collide.
ref: https://stackoverflow.com/questions/56136549/how-can-i-merge-two-argparse-namespaces-in-python-2-x
:param args1:
:param args2:
:return:
"""# - the merged args# The vars() function returns the __dict__ attribute to values of the given object e.g {field:value}.
args = Namespace(**vars(args1), **vars(args2))
return args
test
def merge_args_test():
args1 = Namespace(foo="foo", collided_key='from_args1')
args2 = Namespace(bar="bar", collided_key='from_args2')
args = merge_args(args1, args2)
print('-- merged args')
print(f'{args=}')
output:
Traceback (most recent call last):
File "/Applications/PyCharm.app/Contents/plugins/python/helpers/pydev/pydevd.py", line 1483, in _exec
pydev_imports.execfile(file, globals, locals) # execute the script
File "/Applications/PyCharm.app/Contents/plugins/python/helpers/pydev/_pydev_imps/_pydev_execfile.py", line 18, in execfile
exec(compile(contents+"\n", file, 'exec'), glob, loc)
File "/Users/brando/ultimate-utils/ultimate-utils-proj-src/uutils/__init__.py", line 1202, in <module>
merge_args_test()
File "/Users/brando/ultimate-utils/ultimate-utils-proj-src/uutils/__init__.py", line 1192, in merge_args_test
args = merge_args(args1, args2)
File "/Users/brando/ultimate-utils/ultimate-utils-proj-src/uutils/__init__.py", line 1116, in merge_args
args = Namespace(**vars(args1), **vars(args2))
TypeError: argparse.Namespace() got multiple values for keyword argument 'collided_key'
python-BaseException
you can find it in this library: https://github.com/brando90/ultimate-utils
If you want to have collisions resolved do this:
defmerge_two_dicts(starting_dict: dict, updater_dict: dict) -> dict:"""
Starts from base starting dict and then adds the remaining key values from updater replacing the values from
the first starting/base dict with the second updater dict.
For later: how does d = {**d1, **d2} replace collision?
:param starting_dict:
:param updater_dict:
:return:
"""new_dict: dict = starting_dict.copy() # start with keys and values of starting_dict
new_dict.update(updater_dict) # modifies starting_dict with keys and values of updater_dictreturn new_dict
defmerge_args(args1: Namespace, args2: Namespace) -> Namespace:"""
ref: https://stackoverflow.com/questions/56136549/how-can-i-merge-two-argparse-namespaces-in-python-2-x
:param args1:
:param args2:
:return:
"""# - the merged args# The vars() function returns the __dict__ attribute to values of the given object e.g {field:value}.merged_key_values_for_namespace: dict = merge_two_dicts(vars(args1), vars(args2))
args = Namespace(**merged_key_values_for_namespace)
return args
test:
def merge_args_test():
args1 = Namespace(foo="foo", collided_key='from_args1')
args2 = Namespace(bar="bar", collided_key='from_args2')
args = merge_args(args1, args2)
print('-- merged args')
print(f'{args=}')
assert args.collided_key == 'from_args2', 'Error in merge dict, expected the second argument to be the one used' \
'to resolve collision'
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